检查 Java 中的 NavigableMap 是否为空
Java 中的 isEmpty() 方法用于检查 NavigableMap 是否为空。
首先,创建一个 NavigableMap,并向其中添加元素 -
NavigableMap<Integer, String> n = new TreeMap<Integer, String>(); n.put(5, "Tom"); n.put(9, "John"); n.put(14, "Jamie"); n.put(1, "Tim"); n.put(4, "Jackie"); n.put(15, "Kurt"); n.put(19, "Tiger"); n.put(24, "Jacob");
现在,检查该 Map 是否为空 -
System.out.println("Map is empty? " + n.isEmpty());以下示例演示了如何使用 isEmpty() 方法并检查该 Map 是否为空 -
示例
import java.util.*;
public class Demo {
public static void main(String[] args) {
NavigableMap<Integer, String> n = new TreeMap<Integer, String>();
n.put(5, "Tom");
n.put(9, "John");
n.put(14, "Jamie");
n.put(1, "Tim");
n.put(4, "Jackie");
n.put(15, "Kurt");
n.put(19, "Tiger");
n.put(24, "Jacob");
System.out.println("NavigableMap elements = "+n);
System.out.println("Size = "+n.size());
System.out.println("Map is empty? " + n.isEmpty());
// remove all elements
n.clear();
System.out.println("
Updated NavigableMap elements = "+n);
System.out.println("Size = "+n.size());
System.out.println("Map is empty? " + n.isEmpty());
}
}输出
NavigableMap elements = {1=Tim, 4=Jackie, 5=Tom, 9=John, 14=Jamie, 15=Kurt, 19=Tiger, 24=Jacob}
Size = 8
Map is empty? false
Updated NavigableMap elements = {}
Size = 0
Map is empty? True
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