无递归中序树遍历的 C++ 程序


如果以中序遍历二叉树,则首先访问左子树,接着访问根,然后访问右子树。中序遍历按升序输出键。这是无递归中序树遍历的 C++ 程序。

算法

Begin  
   Function inOrder():
      Declare a stack s.
      Declare the current node as root.
      While current node is not null and stack is not empty do
         While current node is not null do
            Push the current node on the top of the stack
            Make the left child node as current node
         Point the current node at the top of the stack.
         Pop the top most node from the stack
         Print the current node.
         Make the right node as current node.  
      Insert some elements at root, left node and right node in stack.
      Call the inOrder() function to traverse the tree. 
End.

示例代码

 实时演示

#include<bits/stdc++.h>
using namespace std;

struct n {
   int d;
   struct n* l;
   struct n* r;
   n (int d) {
      this->d = d;
      l = r = NULL;
   }
};

void inOrder(struct n *root) {
   stack<n *> s;
   n *current = root;

   while (current != NULL || s.empty() == false) {
      while (current != NULL) {
         s.push(current);
         current = current->l;
      }

      current = s.top();
      s.pop();

      cout << current->d << " ";
      current = current->r;
   }
}

int main() {
   struct n *root = new n(7);

   root->l = new n(6);
   root->r = new n(2);
   root->l->l = new n(1);
   root->l->r = new n(9);

   inOrder(root);
   return 0;
}

输出

1 6 9 7 2

更新日期:2019 年 7 月 30 日

575 次浏览

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