在 NumPy 中返回两个形状不同的掩码数组的外积
要返回两个形状不同的掩码数组的外积,请使用 Python NumPy 中的 **ma.outer()** 方法。第一个参数是输入向量。如果输入不是一维的,则将其展平。第二个参数是第二个输入向量。如果输入不是一维的,则将其展平。
掩码数组是标准 numpy.ndarray 和掩码的组合。掩码要么是 nomask(表示关联数组的任何值均有效),要么是一个布尔数组,它确定关联数组的每个元素的值是否有效。
步骤
首先,导入所需的库 &mius;
import numpy as np
使用 numpy.arange() 方法创建一个包含整数元素的 3D 数组 -
arr1 = np.arange(4).reshape((1, 2, 2))
print("Array1...
", arr1)
print("
Array type...
", arr1.dtype)创建掩码数组 1 -
arr1 = ma.array(arr1)
掩码数组 1 -
arr1[0, 0, 1] = ma.masked
显示掩码数组 1 -
print("
Masked Array1...
",arr1)
创建数组 2,一个使用 numpy.arange() 方法创建的包含整数元素的 2D 数组 -
arr2 = np.arange(6).reshape((3,2))
print("
Array2...
", arr2)
print("
Array type...
", arr2.dtype)创建掩码数组 2 -
arr2 = ma.array(arr2)
掩码数组 2 -
arr2[0, 1] = ma.masked
显示掩码数组 2 -
print("
Masked Array2...
",arr2)
要返回两个形状不同的掩码数组的外积,请使用 ma.outer() 方法 -
print("
Result of outer product...
",np.ma.outer(arr1, arr2))示例
import numpy as np
import numpy.ma as ma
# Array 1
# Creating a 3D array with int elements using the numpy.arange() method
arr1 = np.arange(4).reshape((1, 2, 2))
print("Array1...
", arr1)
print("
Array type...
", arr1.dtype)
# Get the dimensions of the Array
print("
Array Dimensions...
",arr1.ndim)
# Get the shape of the Array
print("
Our Array Shape...
",arr1.shape)
# Get the number of elements of the Array
print("
Elements in the Array...
",arr1.size)
# Create a masked array
arr1 = ma.array(arr1)
# Mask Array1
arr1[0, 0, 1] = ma.masked
# Display Masked Array 1
print("
Masked Array1...
",arr1)
# Array 2
# Creating a 2D array with int elements using the numpy.arange() method
arr2 = np.arange(6).reshape((3,2))
print("
Array2...
", arr2)
print("
Array type...
", arr2.dtype)
# Get the dimensions of the Array
print("
Array Dimensions...
",arr2.ndim)
# Get the shape of the Array
print("
Our Array Shape...
",arr2.shape)
# Get the number of elements of the Array
print("
Elements in the Array...
",arr2.size)
# Create a masked array
arr2 = ma.array(arr2)
# Mask Array2
arr2[0, 1] = ma.masked
# Display Masked Array 2
print("
Masked Array2...
",arr2)
# To return the outer product of two masked arrays with different shapes, use the ma.outer() method in Python Numpy
print("
Result of outer product...
",np.ma.outer(arr1, arr2))输出
Array1... [[[0 1] [2 3]]] Array type... int64 Array Dimensions... 3 Our Array Shape... (1, 2, 2) Elements in the Array... 4 Masked Array1... [[[0 --] [2 3]]] Array2... [[0 1] [2 3] [4 5]] Array type... int64 Array Dimensions... 2 Our Array Shape... (3, 2) Elements in the Array... 6 Masked Array2... [[0 --] [2 3] [4 5]] Result of outer product... [[0 -- 0 0 0 0] [-- -- -- -- -- --] [0 -- 4 6 8 10] [0 -- 6 9 12 15]]
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