C++ STL 中的二分搜索函数


二分搜索是一种搜索算法,用于查找目标值在已排序数组中的位置。二分搜索将目标值与已排序数组的中间元素进行比较。二分搜索的时间复杂度为 O(1)。这是一个 C++ 程序,其中我们实现了各种。C++ STL 中二分搜索函数

算法

Begin
   Initialize the vector of integer values.
   The functions are used here:
   binary_search(start_pointer, end_pointer, value) = Returns true if the value present in array otherwise    false.

   lower_bound(start_pointer, end_pointer, value) = Returns pointer to “position of value” if container 
      contains 1 occurrence of value. Returns pointer to “first position of value” if container contains 
      multiple occurrence of value. Returns pointer to “position of next higher number than value” if container does not contain occurrence of value.

   upper_bound(start_pointer, end_pointer, value) = Returns pointer to “position of next higher valuethan 
      value” if container contains 1 occurrence of value. Returns pointer to “first position of next higher 
      number than last occurrence of value” if container contains multiple occurrence of value. Returns 
      pointer to “position of next higher number than value” if container does not contain occurrence of value.
   Print the results.
End.

示例代码

#include<bits/stdc++.h>
using namespace std;
int main() {
   vector<int> a = {6,7,10,14,16,20};
   if (binary_search(a.begin(), a.end(), 50))
      cout << "50 exists in vector";
   else
      cout << "50 does not exist";
   cout << endl;
   if (binary_search(a.begin(), a.end(), 7))
      cout << "7 exists in the vector";
   else
      cout << "7 does not exist";
   cout << endl;
   cout << "The position of 7 using lower_bound ";
   cout << lower_bound(a.begin(), a.end(), 7) - a.begin();
   cout << endl;
   cout << "The position of 7 using upper_bound ";
   cout << upper_bound(a.begin(), a.end(), 7) - a.begin();
   cout << endl;
}

输出

50 does not exist
7 exists in the vector
The position of 7 using lower_bound 1
The position of 7 using upper_bound 2

更新于: 30-7-2019

918 浏览量

开启您的 职业生涯

通过完成此课程获得认证

开始
广告