C 语言程序,用于打印矩阵边界元素的总和
给定一个矩阵,我们需要打印矩阵的边界元素并显示其总和。
示例
请参考以下给定的矩阵 −
给定矩阵
1 2 3 4 5 6 7 8 9
边界矩阵
1 2 3 4 6 7 8 9
边界元素的总和:1 + 2 + 3 + 4 + 6 + 7 + 8 + 9 = 40
找到边界矩阵总和的逻辑如下−
for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("
"); }
程序
以下是打印矩阵边界元素总和的 C 语言程序 −
#include<stdio.h> #include<limits.h> int main(){ int m, n, sum = 0; printf("
Enter the order of the matrix : "); scanf("%d %d",&m,&n); int i, j; int mat[m][n]; printf("
Input the matrix elements
"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++) scanf("%d",&mat[i][j]); } printf("
Boundary Matrix
"); for(i = 0; i<m; i++){ for(j = 0; j<n; j++){ if (i == 0 || j == 0 || i == n – 1 || j == n – 1){ printf("%d ", mat[i][j]); sum = sum + mat[i][j]; } else printf(" "); } printf("
"); } printf("
Sum of boundary is %d", sum); }
输出
执行上述程序后,将生成以下结果 −
Enter the order of the matrix : 3 3 Input the matrix elements : 1 2 3 4 5 6 7 8 9 Boundary Matrix : 1 2 3 4 6 7 8 9 Sum of boundary is 40
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