Go - 将指针传递给函数
Go 编程语言允许你将指针传递给函数。若要执行此操作,只需将函数参数声明为指针类型即可。
在以下示例中,我们将两个指针传递给一个函数,并改变函数内部的值,该值会反映在调用函数中 -
package main import "fmt" func main() { /* local variable definition */ var a int = 100 var b int = 200 fmt.Printf("Before swap, value of a : %d\n", a ) fmt.Printf("Before swap, value of b : %d\n", b ) /* calling a function to swap the values. * &a indicates pointer to a ie. address of variable a and * &b indicates pointer to b ie. address of variable b. */ swap(&a, &b); fmt.Printf("After swap, value of a : %d\n", a ) fmt.Printf("After swap, value of b : %d\n", b ) } func swap(x *int, y *int) { var temp int temp = *x /* save the value at address x */ *x = *y /* put y into x */ *y = temp /* put temp into y */ }
编译并执行上述代码后,将产生以下结果 -
Before swap, value of a :100 Before swap, value of b :200 After swap, value of a :200 After swap, value of b :100
go_pointers.htm
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