Go - 将指针传递给函数
Go 编程语言允许你将指针传递给函数。若要执行此操作,只需将函数参数声明为指针类型即可。
在以下示例中,我们将两个指针传递给一个函数,并改变函数内部的值,该值会反映在调用函数中 -
package main
import "fmt"
func main() {
/* local variable definition */
var a int = 100
var b int = 200
fmt.Printf("Before swap, value of a : %d\n", a )
fmt.Printf("Before swap, value of b : %d\n", b )
/* calling a function to swap the values.
* &a indicates pointer to a ie. address of variable a and
* &b indicates pointer to b ie. address of variable b.
*/
swap(&a, &b);
fmt.Printf("After swap, value of a : %d\n", a )
fmt.Printf("After swap, value of b : %d\n", b )
}
func swap(x *int, y *int) {
var temp int
temp = *x /* save the value at address x */
*x = *y /* put y into x */
*y = temp /* put temp into y */
}
编译并执行上述代码后,将产生以下结果 -
Before swap, value of a :100 Before swap, value of b :200 After swap, value of a :200 After swap, value of b :100
go_pointers.htm
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