求值:a2n+1×a(2n+1)(2n−1)an(4n−1)×(a2)2n+3.
给定: a2n+1×a(2n+1)(2n−1)an(4n−1)×(a2)2n+3.
求: a2n+1×a(2n+1)(2n−1)an(4n−1)×(a2)2n+3。
解:
a2n+1×a(2n+1)(2n−1)an(4n−1)×(a2)2n+3
=a(2n+1)×a(4n2−1)a(4n2−n)×a(4n+6)
=a(2n+1+4n2−1)a(4n2−n+4n+6)
=a(2n+1+4n2−1−4n2+n−4n−6)
=a(−n−6)
=a−(n+6)
=1a(n+6)
=1an×a6
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