求值:a2n+1×a(2n+1)(2n1)an(4n1)×(a2)2n+3.


给定: a2n+1×a(2n+1)(2n1)an(4n1)×(a2)2n+3.

求: a2n+1×a(2n+1)(2n1)an(4n1)×(a2)2n+3

解: 

a2n+1×a(2n+1)(2n1)an(4n1)×(a2)2n+3

=a(2n+1)×a(4n21)a(4n2n)×a(4n+6)

=a(2n+1+4n21)a(4n2n+4n+6)

=a(2n+1+4n214n2+n4n6)

=a(n6)

=a(n+6)

=1a(n+6)

=1an×a6

更新于: 2022-10-10

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