$4 \frac{4}{5}+\left\{2 \frac{1}{5}-\frac{1}{2}\left(1 \frac{1}{4}-\frac{1}{4}-\frac{1}{5}\right)\right\}$

已知：$4 \frac{4}{5}+\left\{2 \frac{1}{5}-\frac{1}{2}\left(1 \frac{1}{4}-\frac{1}{4}-\frac{1}{5}\right)\right\}$

要求：求解

解答：
 

$4 \frac{4}{5}+\left\{2 \frac{1}{5}-\frac{1}{2}\left(1 \frac{1}{4}-\frac{1}{4}-\frac{1}{5}\right)\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{5}{4}-\frac{1}{4}-\frac{1}{5}\right)\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{5}{4}-\frac{5-4}{20}\right)\right\}$ [4 和 5 的最小公倍数是 20]

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{5}{4}-\frac{1}{20}\right)\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{5\times5-1}{20}\right)\right\}$ [20 和 4 的最小公倍数是 20]

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{25-1}{20}\right)\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{24}{20}\right)\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\left( \frac{6}{5}\right)\right\}$ [24 和 20 都可以被 2 整除]

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{1}{2}\times \frac{6}{5}\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{6}{10}\right\}$

$\frac{24}{5}+\left\{\frac{11}{5}-\frac{3}{5}\right\}$ [6 和 10 都可以被 2 整除]

$\frac{24}{5}+\left\{\frac{11-3}{5}\right\}$

$\frac{24}{5}+\left\{\frac{8}{5}\right\}$

$\frac{24}{5}+\frac{8}{5}$

$\frac{24+8}{8}$

$\frac{32}{8}$

4

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更新于： 2022年10月10日

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