- C 标准库
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- C++ 标准库
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C++ 内存::dynamic_pointer_cast
一种称为强制转换的操作符将数据从一种类型转换为另一种类型。C++ 中的动态强制转换主要用于运行时安全的向下转换。动态转换要起作用,基类中需要有一个虚函数。只有多态基类才能使用动态转换,因为它们使用这些数据来确定安全的向下转换。
语法
以下是 C++ Memory::dynamic_pointer_cast 的语法:
shared_ptr<T> dynamic_pointer_cast (const shared_ptr<U>& sp) noexcept;
参数
sp − 这是一个共享指针。
示例 1
让我们来看下面的例子,我们将执行 dynamic_pointer_cast 并获取输出。
#include <iostream>
#include <exception>
using namespace std;
class Base {
virtual void dummy() {}
};
class Derived: public Base {
int a;
};
int main (){
try {
Base * pba = new Derived;
Base * pbb = new Base;
Derived * pd;
pd = dynamic_cast<Derived*>(pba);
if (pd==0) cout << "Welcome \n";
pd = dynamic_cast<Derived*>(pbb);
if (pd==0) cout << "TutorialsPoint\n";
} catch (exception& e) {
cout << "Exception: " << e.what();
}
return 0;
}
输出
让我们编译并运行上面的程序,这将产生以下结果:
TutorialsPoint
示例 2
考虑下面的例子,其中 dynamic_pointer_cast 在类层次结构中向下/横向转换。
#include <iostream>
#include <memory>
class Base {
public:
int a;
virtual void f() const {
std::cout << "Welcome To\n";
}
virtual ~Base() {}
};
class Derived : public Base {
public:
void f() const override {
std::cout << "TutoriaslPoint\n";
}
~Derived() {}
};
int main(){
auto basePtr = std::make_shared<Base>();
std::cout << "Base pointer: ";
basePtr->f();
auto derivedPtr = std::make_shared<Derived>();
std::cout << "Derived pointer: ";
derivedPtr->f();
basePtr = std::static_pointer_cast<Base>(derivedPtr);
std::cout << "Base pointer to derived : ";
basePtr->f();
auto downcastedPtr = std::dynamic_pointer_cast<Derived>(basePtr);
if (downcastedPtr) {
std::cout << "Downcasted pointer : ";
downcastedPtr->f();
}
}
输出
运行上述代码后,它将显示如下输出:
Base pointer: Welcome To Derived pointer: TutoriaslPoint Base pointer to derived : TutoriaslPoint Downcasted pointer : TutoriaslPoint
示例 3
在下面的例子中,我们将使用 dynamic_pointer_cast 并静态和动态地获取输出。
#include <iostream>
#include <memory>
struct A {
static const char* static_type;
const char* dynamic_type;
A(){
dynamic_type = static_type;
}
};
struct B: A {
static const char* static_type;
B(){
dynamic_type = static_type;
}
};
const char* A::static_type = "Hello";
const char* B::static_type = "Welcome";
int main (){
std::shared_ptr<A> Result;
std::shared_ptr<B> bar;
bar = std::make_shared<B>();
Result = std::dynamic_pointer_cast<A>(bar);
std::cout << "Result in static type: " << Result->static_type << '\n';
std::cout << "Result in dynamic type: " << Result->dynamic_type << '\n';
return 0;
}
输出
代码执行后,将生成如下所示的输出:
Result in static type: Hello Result in dynamic type: Welcome
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