C++ unordered_map::swap() 函数



C++ 的std::unordered_map::swap()函数用于交换第一个unordered_map与另一个unordered_map的内容。当两个unordered_map的元素类型相同时,就会发生交换。

此函数不依赖于大小。如果两个unordered_map具有相同的类型,它将完美地交换unordered_map的元素,无论大小是否相同。

语法

以下是非成员std::unordered_map::swap()函数的语法。

void swap( unordered_map<Key,T,Hash,Pred,Alloc>& first, unordered_map<Key,T,Hash,Pred,Alloc>& second);

参数

  • first - 第一个unordered_map对象。
  • second - 第二个相同类型的unordered_map对象。

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返回值

此函数不返回任何内容。

示例 1

在以下示例中,我们将对两个容器进行交换,一个是包含元素的,另一个是空的。

Open Compiler
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4}, {'e', 5} }; unordered_map<char, int> um2; swap(um1, um2); cout << "Unordered map contains following elements" << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }

输出

让我们编译并运行上述程序,这将产生以下结果:

Unordered map contains following elements
e = 5
a = 1
b = 2
c = 3
d = 4

示例 2

考虑另一种情况,我们将使两个unordered_map相互交换。

Open Compiler
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4}, {'e', 5} }; unordered_map<char, int> um2 = { {'A', 1}, {'B', 2}, {'C', 3}, {'D', 4} }; cout << "um1 contains following elements before swapping: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements before swapping: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; swap(um1, um2); cout << "um1 contains following elements after swapping: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements after swapping: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }

输出

以下是上述代码的输出:

um1 contains following elements before swapping: 
e = 5
d = 4
c = 3
b = 2
a = 1
um2 contains following elements before swapping: 
D = 4
C = 3
B = 2
A = 1
um1 contains following elements after swapping: 
D = 4
C = 3
B = 2
A = 1
um2 contains following elements after swapping: 
e = 5
d = 4
c = 3
b = 2
a = 1

示例 3

让我们看下面的例子,我们将创建两个unordered_map,John和Bob,它们存储科目的分数,现在我们将John和Bob的分数互相交换。

Open Compiler
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<string, int> John = { {"CHE", 85}, {"PHY", 88}, {"MAT", 99}, {"CMS", 86}, {"ENG", 95} }; unordered_map<string, int> Bob = { {"PHY", 90}, {"CHE", 82}, {"MAT", 98}, {"CMS", 88} }; cout<<"Swapping the marks of first unordered map with second unordered_map"<<endl; swap(John, Bob); cout <<"John contains following marks after swapping: " << endl; for (auto & it: John) cout << it.first << " = " << it.second << endl; cout <<"Bob contains following marks after swapping: " << endl; for (auto & it: Bob) cout << it.first << " = " << it.second << endl; return 0; }

输出

上述代码的输出如下:

Swapping the marks of first unordered map with second unordered_map
john contains following marks after swapping: 
CMS = 88
MAT = 98
CHE = 82
PHY = 90
Bob contains following marks after swapping: 
ENG = 95
CMS = 86
MAT = 99
PHY = 88
CHE = 85
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