计算:当x = 2.5且y = 1时,(-8x²y⁶) × (-20xy) 的值。
已知
(-8x²y⁶) × (-20xy)
要求
当x = 2.5, y = 1时,求(-8x²y⁶) × (-20xy) 的值。
解答
(-8x²y⁶) × (-20xy) = (-8) × (-20) × x² × x × y⁶ × y
= 160 × x²⁺¹ × y⁶⁺¹
= 160 × x³ × y⁷
= 160 × (2.5)³ × (1)⁷
= 160 × (5/2)³ × 1
= 160 × 125/8
= 20 × 125
$=2500$
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