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C++ unordered_map::swap() 函数
C++ 的 std::unordered_map::swap() 函数用于交换第一个 unordered_map 与另一个 unordered_map 的内容。当另一个容器类型相同的时候,交换才会发生。
此函数交换元素或键值对,而不会实际对单个元素执行任何复制或移动操作,从而无论大小都能实现常数时间执行。
语法
以下是 std::unordered_map::swap() 函数的语法。
void swap(unordered_map& ump);
参数
- ump − 指示要交换的容器。
返回值
此函数不返回任何值。
示例 1
在下面的示例中,让我们看看 swap() 函数的用法。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4}, {'e', 5} }; unordered_map<char, int> um2; um1.swap(um2); cout << "Unordered map contains following elements" << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
输出
让我们编译并运行上述程序,这将产生以下结果:
Unordered map contains following elements e = 5 a = 1 b = 2 c = 3 d = 4
示例 2
在下面的示例中,我们将执行两个容器之间的交换,并将它们的值互换。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<char, int> um1 = { {'a', 1}, {'b', 2}, {'c', 3}, {'d', 4} }; unordered_map<char, int> um2 = { {'e', 5}, {'f', 6}, {'g', 7}, {'h', 8} }; cout<<"um1 contains following element before swap: "<<endl; for(auto & it:um1){ cout<<it.first<< " = "<<it.second<<endl; } cout<<"um2 contains following element before swap: "<<endl; for(auto & it:um2){ cout<<it.first<< " = "<<it.second<<endl; } um1.swap(um2); cout << "um1 contains following elements after swap: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements after swap: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
输出
以下是上述代码的输出:
um1 contains following element before swap: d = 4 c = 3 b = 2 a = 1 um2 contains following element before swap: h = 8 g = 7 f = 6 e = 5 um1 contains following elements after swap: h = 8 g = 7 f = 6 e = 5 um2 contains following elements after swap: d = 4 c = 3 b = 2 a = 1
示例 3
考虑下面的示例,我们将创建一个两个映射,一个使用 [] 运算符,另一个正常创建,然后交换它们的值。
#include <iostream> #include <unordered_map> using namespace std; int main(void) { unordered_map<string, int> um1; um1["Vivek"] = 80; um1["Aman"] = 85; um1["Akash"] = 90; unordered_map<string, int> um2 = { {"Sarika", 65}, {"Revathi", 95}, {"Daniel", 100} }; cout<<"um1 contains following element before swap: "<<endl; for(auto & it:um1){ cout<<it.first<< " = "<<it.second<<endl; } cout<<"um2 contains following element before swap: "<<endl; for(auto & it:um2){ cout<<it.first<< " = "<<it.second<<endl; } um1.swap(um2); cout << "um1 contains following elements after swap: " << endl; for (auto it = um1.begin(); it != um1.end(); ++it) cout << it->first << " = " << it->second << endl; cout << "um2 contains following elements after swap: " << endl; for (auto it = um2.begin(); it != um2.end(); ++it) cout << it->first << " = " << it->second << endl; return 0; }
输出
上述代码的输出如下:
um1 contains following element before swap: Akash = 90 Aman = 85 Vivek = 80 um2 contains following element before swap: Revathi = 95 Daniel = 100 Sarika = 65 um1 contains following elements after swap: Revathi = 95 Daniel = 100 Sarika = 65 um2 contains following elements after swap: Akash = 90 Aman = 85 Vivek = 80
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