求以下多项式的最大公因式
x2−1,x2+2x−3,x2−3x+2
已知:x2−1,x2+2x−3,x2−3x+2
要求:求HCF
解答
x2−1,x2+2x−3,x2−3x+2
=x2−1=(x+1)(x−1)
=x2+2x−3
= x2+3x−x−3=(x−1)(x+3)
=x2−3x+2
=x2−3x+2=x2−2x−x+2
=(x−1)(x−2)
根据以上计算,给定表达式的HCF为(x−1)
广告
已知:x2−1,x2+2x−3,x2−3x+2
要求:求HCF
解答
x2−1,x2+2x−3,x2−3x+2
=x2−1=(x+1)(x−1)
=x2+2x−3
= x2+3x−x−3=(x−1)(x+3)
=x2−3x+2
=x2−3x+2=x2−2x−x+2
=(x−1)(x−2)
根据以上计算,给定表达式的HCF为(x−1)