求以下乘积
$\frac{4}{3}a(a^2 + b^2 - 3c^2)$
已知
$\frac{4}{3}a(a^2 + b^2 - 3c^2)$
要求
我们需要求出给定的乘积。
解答
$\frac{4}{3} a(a^{2}+b^{2}-3 c^{2})=\frac{4}{3} a \times a^{2}+\frac{4}{3} a \times b^{2}+\frac{4}{3} a \times(-3 c^{2})$
$=\frac{4}{3} a^{1+2}+\frac{4}{3} a \times b^{2}-4 \times a \times c^{2}$
$=\frac{4}{3} a^{3}+\frac{4}{3} a b^{2}-4 a c^{2}$
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