加法
(i). 3mn, −5mn, 8mn, −4mn
(ii). t−8tz, 3tz−z, z−t
(iii). −7mn+5, 12mn+2, 9mn−8, −2mn−3
(iv). a+b−3, b−a+3, a−b+3
(v). 14x+10y−12xy−13, 18−7x−10y+8xy, 4xy
(vi). 5m−7n, 3n−4m+2, 2m−3mn−5
(vii). 4x2y, −3xy2, −5xy2, 5x2y
(viii). 3p2q2−4pq+5, −10p2q2, 15+9pq+7p2q2
(ix). ab−4a, 4b−ab, 4a−4b
(x). x2−y2−1, y2−1−x2, 1−x2−y2
需要完成的任务:求和
(i). 3mn, −5mn, 8mn, −4mn
(ii). t−8tz, 3tz−z, z−t
(iii). −7mn+5, 12mn+2, 9mn−8, −2mn−3
(iv). a+b−3, b−a+3, a−b+3
(v). 14x+10y−12xy−13, 18−7x−10y+8xy, 4xy
(vi). 5m−7n, 3n−4m+2, 2m−3mn−5
(vii). 4x2y, −3xy2, −5xy2, 5x2y
(viii). 3p2q2−4pq+5, −10p2q2, 15+9pq+7p2q2
(ix). ab−4a, 4b−ab, 4a−4b
(x). x2−y2−1, y2−1−x2, 1−x2−y2
解答:
i) 3mn, −5mn, 8mn, −4mn
=(3mn)+(−5mn)+(8mn)+(−4mn)
=(3−5+8−4)mn
=2mn
ii) t−8tz, 3tz−z, z−t
=(t−8tz)+(3tz−z)+(z−t)
=t−8tz+3tz−z+z−t
=t−t−8tz+3tz−z+z
=−5tz
iii) $– 7mn + 5 + 12mn + 2 + (9mn – 8) + (- 2mn – 3) = – 7mn + 5 + 12mn + 2 + 9mn – 8 – 2mn – 3$
=–7mn+12mn+9mn–2mn+5+2–8–3
=mn(−7+12+9–2)+(5+2–8–3)
=mn(−9+21)+(7–11)
=mn(12)–4
=12mn–4
iv) a+b−3, b−a+3, a−b+3
=(a+b−3)+(b−a+3)+(a−b+3)
=a−a+a+b+b−b−3+3+3
=a(1−1+1)+b (1+1−1)+3 (−1+1+1)
=a+b+3
v) 14x+10y−12xy−13, 18−7x−10y+8xy, 4xy
=(14x+10y−12xy−13)+(18−7x−10y+8yx)+4xy
=14x−7x+10y−10y−12xy+8yx+4xy−13+18
=x(14−7)+y(10−10)+xy (−12+8+4)−13+18
=7x+5
vi) 5m−7n, 3n−4m+2, 2m−3mn−5
=(5m−7n)+(3n−4m+2)+(2m−3mn−5)
=5m−4m+2m−7n+3n−3mn+2−5
=m(5−4+2)+n(−7+3)−3mn+2−5
=3m−4n−3mn−3
vii) 4x2y,−3xy2,−5xy2, 5x2y
=x2y (4+5)+xy2 (−3−5)
=9x2y−8xy2
viii) 3p2q2−4pq+5, −10p2q2, 15+9pq+7p2q2
=(3p2q2−4pq+5)+(−10p2q2)+(15+9pq+7p2q2)
=3p2q2−10p2q2+7p2q2−4pq+9pq+5+15
=p2q2(3−10+7)+pq(−4+9)+5+15
=5pq+20
ix) ab−4a, 4b−ab, 4a−4b
=(ab−4a)+(4b−ab)+(4a−4b)
=ab−ab−4a+4a+4b−4b
=ab(1−1)+a(−4+4)+b(4−4)
=0
x) x2−y2−1, y2−1−x2, 1−x2−y2
=(x2−y2−1)+(y2−1−x2)+(1−x2−y2)
=x2−x2−x2−y2+y2−y2−1−1+1
=x2 (1−1−1)+y2(−1+1−1)+(−1−1+1)
=−x2−y2−1