PHP mysqli_stmt_error() 函数



定义和用法

mysqli_stmt_error() 函数返回执行最后一条语句期间发生的错误的描述。

语法

mysqli_stmt_error($stmt)

参数

序号 参数及描述
1

stmt(必填)

这是一个表示语句的对象。

返回值

PHP mysqli_stmt_error() 函数返回一个字符串值,表示执行最后一条语句期间发生的错误的描述。如果没有任何错误,此函数返回一个空字符串。

PHP 版本

此函数首次引入于 PHP 5 版本,并在所有后续版本中均有效。

示例

以下示例演示了 mysqli_stmt_error() 函数(以过程式风格)的用法:

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   mysqli_query($con, "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = mysqli_prepare($con, "SELECT * FROM myplayers");

   mysqli_query($con, "DROP TABLE myplayers");

   //Executing the statement
   mysqli_stmt_execute($stmt);

   //Error 
   $error = mysqli_stmt_error($stmt);
   print("Error : ".$error);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

这将产生以下结果:

Table Created.....
Record Inserted.....
Error : Table 'mydb.myplayers' doesn't exist

示例

在面向对象风格中,此函数的语法为 $con ->error。以下是此函数在面向对象风格中的示例:

<?php
   //Creating a connection
   $con = new mysqli("localhost", "root", "password", "mydb");

   $con -> query("CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   $con -> query("INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = $con ->prepare("SELECT * FROM myplayers");

   $con ->query("DROP TABLE myplayers");

   //Executing the statement
   $stmt->execute();

   //Error
   $error = $stmt ->error;
   print("Error: ".$error);

   //Closing the statement
   $stmt->close();

   //Closing the connection
   $con->close();
?>

这将产生以下结果:

Table Created.....
Record Inserted.....
Error : Table 'mydb.myplayers' doesn't exist

示例

如果最后执行的语句对象中没有任何错误,则此函数返回一个空字符串:

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");

   $query = "INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India'),(2, 'Jonathan', 'Trott', 'CapeTown', 'SouthAfrica'),(3, 'Kumara', 'Sangakkara', 'Matale', 'Srilanka')";

   //Preparing a statement
   $stmt = mysqli_prepare($con, $query);

   //Executing the statement
   mysqli_stmt_execute($stmt);
   print("Record Inserted.....\n");

   //Error 
   $error = mysqli_stmt_error($stmt);
   print("Error : ".$error);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);

?>

这将产生以下结果:

Table Created.....
Record Inserted.....
Error :
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