PHP mysqli_stmt_sqlstate() 函数

定义和用法

mysqli_stmt_sqlstate() 函数返回执行最后一条语句时发生的 SQLSTATE 错误。

语法

mysqli_stmt_sqlstate($stmt);

参数

返回值

PHP mysqli_stmt_sqlstate() 函数返回一个字符串值，表示执行最后一条语句时发生的 SQLSTATE 错误。如果没有错误，此函数返回 00000。

PHP 版本

此函数首次在 PHP 5 版本中引入，并在所有后续版本中均有效。

示例

以下示例演示了 mysqli_stmt_sqlstate() 函数（在过程式风格中）的用法：

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE emp(ID INT, FirstName VARCHAR(20))");
   print("Table Created.....\n");

   $stmt = mysqli_prepare($con, "INSERT INTO emp (ID) VALUES (?)");
   mysqli_stmt_bind_param($stmt, "s", $id);
   $id = 'test';

   //Executing the statement
   mysqli_stmt_execute($stmt);
   //State
   $state = mysqli_stmt_sqlstate($stmt);
   print("state: ".$state);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

这将产生以下结果：

Table Created.....
state: HY000

示例

在面向对象风格中，此函数的语法为 $con->sqlstate。以下是此函数在面向对象风格中的示例：

<?php
   //Creating a connection
   $con = new mysqli("localhost", "root", "password", "mydb");

   $con -> query("CREATE TABLE myplayers(ID INT, First_Name VARCHAR(255), Last_Name VARCHAR(255), Place_Of_Birth VARCHAR(255), Country VARCHAR(255))");
   print("Table Created.....\n");
   $con -> query("INSERT INTO myplayers values(1, 'Sikhar', 'Dhawan', 'Delhi', 'India')");
   print("Record Inserted.....\n");

   $stmt = $con ->prepare("SELECT * FROM myplayers");

   $con ->query("DROP TABLE myplayers");

   //Executing the statement
   $stmt->execute();

   //SQl State
   $state = $stmt ->sqlstate;
   print("SQL State: ".$state);

   //Closing the statement
   $stmt->close();

   //Closing the connection
   $con->close();
?>

这将产生以下结果：

Table Created.....
Record Inserted.....
SQL State: 42S02

示例

以下是 mysqli_stmt_sqlstate() 函数的另一个示例：

<?php
   $con = mysqli_connect("localhost", "root", "password", "mydb");

   mysqli_query($con, "CREATE TABLE emp(ID INT, FirstName VARCHAR(20), LastName VARCHAR(5), DateOfBirth VARCHAR(255), Salary INT)");
   print("Table Created.....\n");

   $stmt = mysqli_prepare($con, "INSERT INTO emp values(?, ?, ?, ?, ?)");
   mysqli_stmt_bind_param($stmt, "isssi", $id, $fname, $lname, $pob, $country);
   $id = 1;
   $fname = 'Swetha';
   $lname = 'Yellapragada';
   $dob = DATE('1981-12-05');
   $country = 2366;
   //Executing the statement
   mysqli_stmt_execute($stmt);
   //Warnings
   $state = mysqli_stmt_sqlstate($stmt);
   print("state: ".$state);

   //Closing the statement
   mysqli_stmt_close($stmt);

   //Closing the connection
   mysqli_close($con);
?>

这将产生以下结果：

Table Created.....
state: 22001