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双向链表数据结构
什么是双向链表?
双向链表是链表的一种变体,与单向链表相比,它可以轻松地双向导航(向前和向后)。以下是一些理解双向链表概念的重要术语。
链接 − 链表的每个链接都可以存储称为元素的数据。
下一个 − 链表的每个链接都包含一个指向下一个链接的链接,称为“下一个”。
前一个 − 链表的每个链接都包含一个指向前一个链接的链接,称为“前一个”。
链表 − 链表包含指向第一个链接(称为“第一个”)和最后一个链接(称为“最后一个”)的连接链接。
双向链表表示
根据以上说明,以下是要考虑的重要事项。
双向链表包含一个称为“第一个”和“最后一个”的链接元素。
每个链接都包含一个或多个数据字段和一个称为“下一个”的链接字段。
每个链接都使用其“下一个”链接与其下一个链接链接。
每个链接都使用其“前一个”链接与其前一个链接链接。
最后一个链接包含一个空链接,以标记列表的结尾。
双向链表的基本操作
以下是列表支持的基本操作。
插入 − 在列表开头添加一个元素。
插入末尾 − 在列表末尾添加一个元素。
插入到之后 − 在列表的一个项目之后添加一个元素。
删除 − 删除列表开头的元素。
删除末尾 − 删除列表末尾的元素。
删除 − 使用键从列表中删除一个元素。
向前显示 − 以向前的方式显示整个列表。
向后显示 − 以向后的方式显示整个列表。
双向链表 - 在开头插入
在此操作中,我们创建一个具有三个部分的新节点,一个包含数据,其他两个包含其在列表中前一个和下一个节点的地址。此新节点插入到列表的开头。
算法
1. START 2. Create a new node with three variables: prev, data, next. 3. Store the new data in the data variable 4. If the list is empty, make the new node as head. 5. Otherwise, link the address of the existing first node to the next variable of the new node, and assign null to the prev variable. 6. Point the head to the new node. 7. END
示例
以下是此操作在各种编程语言中的实现:
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <stdbool.h> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } void main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("\nDoubly Linked List: "); printList(); }
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)
#include <iostream> #include <cstring> #include <cstdlib> #include <cstdbool> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } int main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("Doubly Linked List: "); printList(); return 0; }
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)
//Java code for doubly linked list import java.util.*; class Node { public int data; public int key; public Node next; public Node prev; public Node(int data, int key) { this.data = data; this.key = key; this.next = null; this.prev = null; } } public class Main { //this link always point to first Link static Node head = null; //this link always point to last Link static Node last = null; static Node current = null; // is list empty public static boolean is_empty() { return head == null; } //display the doubly linked list public static void print_list() { Node ptr = head; while (ptr != null) { System.out.println("(" + ptr.key + "," + ptr.data + ")"); ptr = ptr.next; } } //insert link at the first location public static void insert_first(int key, int data) { //create a link Node link = new Node(data, key); if (is_empty()) { //make it the last link last = link; } else { //update first prev link head.prev = link; } //point it to old first link link.next = head; //point first to new first link head = link; } public static void main(String[] args) { insert_first(1, 10); insert_first(2, 20); insert_first(3, 30); insert_first(4, 1); insert_first(5, 40); insert_first(6, 56); System.out.println("Doubly Linked List: "); print_list(); } }
输出
Doubly Linked List: (6,56)(5,40)(4,1)(3,30)(2,20)(1,10)
#Python code for doubly linked list class Node: def __init__(self, data=None, key=None): self.data = data self.key = key self.next = None self.prev = None #this link always point to first Link head = None #this link always point to last Link last = None current = None #is list empty def is_empty(): return head == None #display the doubly linked list def print_list(): ptr = head while ptr != None: print(f"({ptr.key},{ptr.data})") ptr = ptr.next #insert link at the first location def insert_first(key, data): global head, last #create a link link = Node(data, key) if is_empty(): #make it the last link last = link else: #update first prev link head.prev = link #point it to old first link link.next = head #point first to new first link head = link insert_first(1,10) insert_first(2,20) insert_first(3,30) insert_first(4,1) insert_first(5,40) insert_first(6,56) print("Doubly Linked List: ") print_list()
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10)
双向链表 - 在末尾插入
在此插入操作中,新的输入节点将添加到双向链表的末尾;如果列表非空。如果列表为空,则头将指向新节点。
算法
1. START 2. If the list is empty, add the node to the list and point the head to it. 3. If the list is not empty, find the last node of the list. 4. Create a link between the last node in the list and the new node. 5. The new node will point to NULL as it is the new last node. 6. END
示例
以下是此操作在各种编程语言中的实现:
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <stdbool.h> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //insert link at the last location void insertLast(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //make link a new last link last->next = link; //mark old last node as prev of new link link->prev = last; } //point last to new last node last = link; } void main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertLast(5,40); insertLast(6,56); printf("Doubly Linked List: "); printList(); }
输出
Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
#include <iostream> #include <cstring> #include <cstdlib> #include <cstdbool> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //insert link at the last location void insertLast(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //make link a new last link last->next = link; //mark old last node as prev of new link link->prev = last; } //point last to new last node last = link; } int main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertLast(5,40); insertLast(6,56); printf("Doubly Linked List: "); printList(); return 0; }
输出
Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
import java.util.*; class Node { public int data; public int key; public Node next; public Node prev; public Node(int data, int key) { this.data = data; this.key = key; this.next = null; this.prev = null; } } public class Main { static Node head = null; static Node last = null; static Node current = null; public static boolean isEmpty() { return head == null; } public static void printList() { Node ptr = head; while (ptr != null) { System.out.print("(" + ptr.key + "," + ptr.data + ") "); ptr = ptr.next; } } public static void insertFirst(int key, int data) { Node link = new Node(data, key); if (isEmpty()) { last = link; } else { head.prev = link; } link.next = head; head = link; } public static void insertLast(int key, int data) { Node link = new Node(data, key); if (isEmpty()) { last = link; } else { last.next = link; link.prev = last; } last = link; } public static void main(String[] args) { insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertLast(5,40); insertLast(6,56); System.out.print("Doubly Linked List: "); printList(); } }
输出
Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
class Node: def __init__(self, data=None, key=None): self.data = data self.key = key self.next = None self.prev = None head = None last = None current = None def isEmpty(): return head == None def printList(): ptr = head while ptr != None: print(f"({ptr.key},{ptr.data})", end=" ") ptr = ptr.next def insertFirst(key, data): global head, last link = Node(data, key) if isEmpty(): last = link else: head.prev = link link.next = head head = link def insertLast(key, data): global head, last link = Node(data, key) if isEmpty(): last = link else: last.next = link link.prev = last last = link insertFirst(1,10) insertFirst(2,20) insertFirst(3,30) insertFirst(4,1) insertLast(5,40) insertLast(6,56) print("Doubly Linked List: ", end="") printList()
输出
Doubly Linked List: (4,1) (3,30) (2,20) (1,10) (5,40) (6,56)
双向链表 - 在开头删除
此删除操作删除双向链表中现有的第一个节点。头将移至下一个节点,并删除链接。
算法
1. START 2. Check the status of the doubly linked list 3. If the list is empty, deletion is not possible 4. If the list is not empty, the head pointer is shifted to the next node. 5. END
示例
以下是此操作在各种编程语言中的实现:
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <stdbool.h> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //delete first item struct node* deleteFirst(){ //save reference to first link struct node *tempLink = head; //if only one link if(head->next == NULL) { last = NULL; } else { head->next->prev = NULL; } head = head->next; //return the deleted link return tempLink; } void main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("Doubly Linked List: \n"); printList(); printf("\nList after deleting first record: \n"); deleteFirst(); printList(); }
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
#include <iostream> #include <cstring> #include <cstdlib> #include <cstdbool> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the doubly linked list void printList(){ struct node *ptr = head; while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //delete first item struct node* deleteFirst(){ //save reference to first link struct node *tempLink = head; //if only one link if(head->next == NULL) { last = NULL; } else { head->next->prev = NULL; } head = head->next; //return the deleted link return tempLink; } int main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("Doubly Linked List: \n"); printList(); printf("\nList after deleting first record: \n"); deleteFirst(); printList(); return 0; }
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
//Java code for doubly linked list import java.util.*; class Node { public int data; public int key; public Node next; public Node prev; public Node(int data, int key) { this.data = data; this.key = key; this.next = null; this.prev = null; } } public class Main { //this link always point to first Link public static Node head = null; //this link always point to last Link public static Node last = null; //this link always point to current Link public static Node current = null; //is list empty public static boolean isEmpty() { return head == null; } //display the doubly linked list public static void printList() { Node ptr = head; while (ptr != null) { System.out.print("(" + ptr.key + "," + ptr.data + ") "); ptr = ptr.next; } } //insert link at the first location public static void insertFirst(int key, int data) { //create a link Node link = new Node(data, key); if (isEmpty()) { //make it the last link last = link; } else { //update first prev link head.prev = link; } //point it to old first link link.next = head; head = link; } //delete the first item public static Node deleteFirst() { //save reference to first link Node tempLink = head; //if only one link if (head.next == null) { last = null; } else { head.next.prev = null; } head = head.next; //return the deleted link return tempLink; } public static void main(String[] args) { insertFirst(1, 10); insertFirst(2, 20); insertFirst(3, 30); insertFirst(4, 1); insertFirst(5, 40); insertFirst(6, 56); System.out.print("Doubly Linked List: \n"); printList(); System.out.print("\nList after deleting first record: \n"); deleteFirst(); printList(); } }
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
#Python code for doubly linked list class Node: def __init__(self, data=None, key=None): self.data = data self.key = key self.next = None self.prev = None #this link always point to first Link head = None #this link always point to last Link last = None current = None #is list empty def isEmpty(): return head == None #display the doubly linked list def printList(): ptr = head while ptr != None: print(f"({ptr.key},{ptr.data}) ", end="") ptr = ptr.next #insert link at the first location def insertFirst(key, data): #create a link global head, last link = Node(data, key) if isEmpty(): #make it the last link last = link else: #update first prev link head.prev = link #point it to old first link link.next = head head = link #delete first item def deleteFirst(): #save reference to first link global head, last tempLink = head #if only one link if head.next == None: last = None else: head.next.prev = None head = head.next #return the deleted link return tempLink insertFirst(1,10) insertFirst(2,20) insertFirst(3,30) insertFirst(4,1) insertFirst(5,40) insertFirst(6,56) print("Doubly Linked List:") printList() print("\nList after deleting first record:") deleteFirst() printList()
输出
Doubly Linked List: (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) List after deleting first record: (5,40) (4,1) (3,30) (2,20) (1,10)
双向链表 - 完整实现
以下是双向链表在各种编程语言中的完整实现:
#include <stdio.h> #include <string.h> #include <stdlib.h> #include <stdbool.h> struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the list in from first to last void displayForward(){ //start from the beginning struct node *ptr = head; //navigate till the end of the list printf("\n[ "); while(ptr != NULL) { printf("(%d,%d) ",ptr->key,ptr->data); ptr = ptr->next; } printf(" ]"); } //display the list from last to first void displayBackward(){ //start from the last struct node *ptr = last; //navigate till the start of the list printf("\n[ "); while(ptr != NULL) { //print data printf("(%d,%d) ",ptr->key,ptr->data); //move to next item ptr = ptr ->prev; printf(" "); } printf(" ]"); } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //insert link at the last location void insertLast(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //make link a new last link last->next = link; //mark old last node as prev of new link link->prev = last; } //point last to new last node last = link; } //delete first item struct node* deleteFirst(){ //save reference to first link struct node *tempLink = head; //if only one link if(head->next == NULL) { last = NULL; } else { head->next->prev = NULL; } head = head->next; //return the deleted link return tempLink; } //delete link at the last location struct node* deleteLast(){ //save reference to last link struct node *tempLink = last; //if only one link if(head->next == NULL) { head = NULL; } else { last->prev->next = NULL; } last = last->prev; //return the deleted link return tempLink; } //delete a link with given key struct node* delete(int key){ //start from the first link struct node* current = head; struct node* previous = NULL; //if list is empty if(head == NULL) { return NULL; } //navigate through list while(current->key != key) { //if it is last node if(current->next == NULL) { return NULL; } else { //store reference to current link previous = current; //move to next link current = current->next; } } //found a match, update the link if(current == head) { //change first to point to next link head = head->next; } else { //bypass the current link current->prev->next = current->next; } if(current == last) { //change last to point to prev link last = current->prev; } else { current->next->prev = current->prev; } return current; } bool insertAfter(int key, int newKey, int data){ //start from the first link struct node *current = head; //if list is empty if(head == NULL) { return false; } //navigate through list while(current->key != key) { //if it is last node if(current->next == NULL) { return false; } else { //move to next link current = current->next; } } //create a link struct node *newLink = (struct node*) malloc(sizeof(struct node)); newLink->key = key; newLink->data = data; if(current == last) { newLink->next = NULL; last = newLink; } else { newLink->next = current->next; current->next->prev = newLink; } newLink->prev = current; current->next = newLink; return true; } int main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("\nList (First to Last): "); displayForward(); printf("\n"); printf("\nList (Last to first): "); displayBackward(); printf("\nList , after deleting first record: "); deleteFirst(); displayForward(); printf("\nList , after deleting last record: "); deleteLast(); displayForward(); printf("\nList , insert after key(4) : "); insertAfter(4,7, 13); displayForward(); printf("\nList , after delete key(4) : "); delete(4); displayForward(); }
输出
List (First to Last): [ (6,56) (5,40) (4,1) (3,30) (2,20) (1,10) ] List (Last to first): [ (1,10) (2,20) (3,30) (4,1) (5,40) (6,56) ] List , after deleting first record: [ (5,40) (4,1) (3,30) (2,20) (1,10) ] List , after deleting last record: [ (5,40) (4,1) (3,30) (2,20) ] List , insert after key(4) : [ (5,40) (4,1) (4,13) (3,30) (2,20) ] List , after delete key(4) : [ (5,40) (4,13) (3,30) (2,20) ]
#include <iostream> #include <cstring> #include <cstdlib> #include <cstdbool> using namespace std; struct node { int data; int key; struct node *next; struct node *prev; }; //this link always point to first Link struct node *head = NULL; //this link always point to last Link struct node *last = NULL; struct node *current = NULL; //is list empty bool isEmpty(){ return head == NULL; } //display the list in from first to last void displayForward(){ //start from the beginning struct node *ptr = head; //navigate till the end of the list cout << "\n[ "; while(ptr != NULL) { cout << "(" << ptr->key << "," << ptr->data << ")"; ptr = ptr->next; } cout << " ]" << endl; } //display the list from last to first void displayBackward(){ //start from the last struct node *ptr = last; //navigate till the start of the list cout << "\n[ "; while(ptr != NULL) { //print data cout << "(" << ptr->key << "," << ptr->data << ")"; //move to next item ptr = ptr ->prev; cout << " "; } cout << " ]" << endl; } //insert link at the first location void insertFirst(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //update first prev link head->prev = link; } //point it to old first link link->next = head; //point first to new first link head = link; } //insert link at the last location void insertLast(int key, int data){ //create a link struct node *link = (struct node*) malloc(sizeof(struct node)); link->key = key; link->data = data; if(isEmpty()) { //make it the last link last = link; } else { //make link a new last link last->next = link; //mark old last node as prev of new link link->prev = last; } //point last to new last node last = link; } //delete first item struct node* deleteFirst(){ //save reference to first link struct node *tempLink = head; //if only one link if(head->next == NULL) { last = NULL; } else { head->next->prev = NULL; } head = head->next; //return the deleted link return tempLink; } //delete link at the last location struct node* deleteLast(){ //save reference to last link struct node *tempLink = last; //if only one link if(head->next == NULL) { head = NULL; } else { last->prev->next = NULL; } last = last->prev; //return the deleted link return tempLink; } //delete a link with given key struct node* deletenode(int key){ //start from the first link struct node* current = head; struct node* previous = NULL; //if list is empty if(head == NULL) { return NULL; } //navigate through list while(current->key != key) { //if it is last node if(current->next == NULL) { return NULL; } else { //store reference to current link previous = current; //move to next link current = current->next; } } //found a match, update the link if(current == head) { //change first to point to next link head = head->next; } else { //bypass the current link current->prev->next = current->next; } if(current == last) { //change last to point to prev link last = current->prev; } else { current->next->prev = current->prev; } return current; } bool insertAfter(int key, int newKey, int data){ //start from the first link struct node *current = head; //if list is empty if(head == NULL) { return false; } //navigate through list while(current->key != key) { //if it is last node if(current->next == NULL) { return false; } else { //move to next link current = current->next; } } //create a link struct node *newLink = (struct node*) malloc(sizeof(struct node)); newLink->key = key; newLink->data = data; if(current == last) { newLink->next = NULL; last = newLink; } else { newLink->next = current->next; current->next->prev = newLink; } newLink->prev = current; current->next = newLink; return true; } int main(){ insertFirst(1,10); insertFirst(2,20); insertFirst(3,30); insertFirst(4,1); insertFirst(5,40); insertFirst(6,56); printf("\nList (First to Last): "); displayForward(); printf("\n"); printf("\nList (Last to first): "); displayBackward(); printf("\nList , after deleting first record: "); deleteFirst(); displayForward(); printf("\nList , after deleting last record: "); deleteLast(); displayForward(); printf("\nList , insert after key(4) : "); insertAfter(4, 7, 13); displayForward(); printf("\nList , after delete key(4) : "); deletenode(4); displayForward(); return 0; }
输出
List (First to Last): [ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List (Last to First): [ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ] List, after deleting first record: [ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List, after deleting last record: [ (5, 40) (4, 1) (3, 30) (2, 20) ] List, insert after key(4): [ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ] List, after delete key(4): [ (5, 40) (7, 13) (3, 30) (2, 20) ]
class Node { int data; int key; Node next; Node prev; public Node(int key, int data) { this.key = key; this.data = data; this.next = null; this.prev = null; } } class DoublyLinkedList { Node head; Node last; boolean isEmpty() { return head == null; } void displayForward() { Node ptr = head; System.out.print("[ "); while (ptr != null) { System.out.print("(" + ptr.key + "," + ptr.data + ") "); ptr = ptr.next; } System.out.println("]"); } void displayBackward() { Node ptr = last; System.out.print("[ "); while (ptr != null) { System.out.print("(" + ptr.key + "," + ptr.data + ") "); ptr = ptr.prev; } System.out.println("]"); } void insertFirst(int key, int data) { Node link = new Node(key, data); if (isEmpty()) { last = link; } else { head.prev = link; } link.next = head; head = link; } void insertLast(int key, int data) { Node link = new Node(key, data); if (isEmpty()) { last = link; } else { last.next = link; link.prev = last; } last = link; } Node deleteFirst() { if (isEmpty()) { return null; } Node tempLink = head; if (head.next == null) { last = null; } else { head.next.prev = null; } head = head.next; return tempLink; } Node deleteLast() { if (isEmpty()) { return null; } Node tempLink = last; if (head.next == null) { head = null; } else { last.prev.next = null; } last = last.prev; return tempLink; } Node delete(int key) { Node current = head; Node previous = null; if (head == null) { return null; } while (current.key != key) { if (current.next == null) { return null; } else { previous = current; current = current.next; } } if (current == head) { head = head.next; } else { current.prev.next = current.next; } if (current == last) { last = current.prev; } else { current.next.prev = current.prev; } return current; } boolean insertAfter(int key, int newKey, int data) { Node current = head; if (head == null) { return false; } while (current.key != key) { if (current.next == null) { return false; } else { current = current.next; } } Node newLink = new Node(newKey, data); if (current == last) { newLink.next = null; last = newLink; } else { newLink.next = current.next; current.next.prev = newLink; } newLink.prev = current; current.next = newLink; return true; } } public class Main { public static void main(String[] args) { DoublyLinkedList dll = new DoublyLinkedList(); dll.insertFirst(1, 10); dll.insertFirst(2, 20); dll.insertFirst(3, 30); dll.insertFirst(4, 1); dll.insertFirst(5, 40); dll.insertFirst(6, 56); System.out.println("List (First to Last):"); dll.displayForward(); System.out.println(); System.out.println("List (Last to First):"); dll.displayBackward(); System.out.println("List, after deleting first record:"); dll.deleteFirst(); dll.displayForward(); System.out.println("List, after deleting last record:"); dll.deleteLast(); dll.displayForward(); System.out.println("List, insert after key(4):"); dll.insertAfter(4, 7, 13); dll.displayForward(); System.out.println("List, after delete key(4):"); dll.delete(4); dll.displayForward(); } }
输出
List (First to Last): [ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List (Last to First): [ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ] List, after deleting first record: [ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List, after deleting last record: [ (5, 40) (4, 1) (3, 30) (2, 20) ] List, insert after key(4): [ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ] List, after delete key(4): [ (5, 40) (7, 13) (3, 30) (2, 20) ]
class Node: def __init__(self, key, data): self.key = key self.data = data self.next = None self.prev = None class DoublyLinkedList: def __init__(self): self.head = None self.last = None def is_empty(self): return self.head is None def display_forward(self): ptr = self.head print("[", end=" ") while ptr: print("({}, {})".format(ptr.key, ptr.data), end=" ") ptr = ptr.next print("]") def display_backward(self): ptr = self.last print("[", end=" ") while ptr: print("({}, {})".format(ptr.key, ptr.data), end=" ") ptr = ptr.prev print("]") def insert_first(self, key, data): link = Node(key, data) if self.is_empty(): self.last = link else: self.head.prev = link link.next = self.head self.head = link def insert_last(self, key, data): link = Node(key, data) if self.is_empty(): self.last = link else: self.last.next = link link.prev = self.last self.last = link def delete_first(self): if self.is_empty(): return None temp_link = self.head if self.head.next is None: self.last = None else: self.head.next.prev = None self.head = self.head.next return temp_link def delete_last(self): if self.is_empty(): return None temp_link = self.last if self.head.next is None: self.head = None else: self.last.prev.next = None self.last = self.last.prev return temp_link def delete(self, key): current = self.head while current and current.key != key: current = current.next if current is None: return None if current == self.head: self.head = self.head.next else: current.prev.next = current.next if current == self.last: self.last = current.prev else: current.next.prev = current.prev return current def insert_after(self, key, new_key, data): current = self.head while current and current.key != key: current = current.next if current is None: return False new_link = Node(new_key, data) if current == self.last: new_link.next = None self.last = new_link else: new_link.next = current.next current.next.prev = new_link new_link.prev = current current.next = new_link return True # Example usage dll = DoublyLinkedList() dll.insert_first(1, 10) dll.insert_first(2, 20) dll.insert_first(3, 30) dll.insert_first(4, 1) dll.insert_first(5, 40) dll.insert_first(6, 56) print("List (First to Last):") dll.display_forward() print() print("List (Last to First):") dll.display_backward() print("List, after deleting first record:") dll.delete_first() dll.display_forward() print("List, after deleting last record:") dll.delete_last() dll.display_forward() print("List, insert after key(4):") dll.insert_after(4, 7, 13) dll.display_forward() print("List, after delete key(4):") dll.delete(4) dll.display_forward()
输出
List (First to Last): [ (6, 56) (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List (Last to First): [ (1, 10) (2, 20) (3, 30) (4, 1) (5, 40) (6, 56) ] List, after deleting first record: [ (5, 40) (4, 1) (3, 30) (2, 20) (1, 10) ] List, after deleting last record: [ (5, 40) (4, 1) (3, 30) (2, 20) ] List, insert after key(4): [ (5, 40) (4, 1) (7, 13) (3, 30) (2, 20) ] List, after delete key(4): [ (5, 40) (7, 13) (3, 30) (2, 20) ]