条形图 - 例题解析

答案 - B

解释

Total number of girls =  (25+30+20+30+32.5) thousand = 137.5*1000 = 137500. 
∴  Average number of girls = 137500/5 = 27500

答案 - A

解释

Total number of girls in collages D and E  =(30+32.5) thousand = (62.5*1000) = 62500.
Total number of girls in collages A,B and C=   (25+30+20) thousands = (75*1000)= 75000
∴  Required  % = (62500/75000*100)= 83.3% 

答案 - C

解释

Total number of boys = (22.5+25+30+22.5+22.5) thousands =(122.5*1000) = 122500
Total number of girls =  (25+30+20+30+32.5) thousand = 137.5*1000 = 137500. 
∴   Required difference = (137500-122500)= 15000

答案 - C

解释

Required ratio = (22.5*1000): (25*1000)=   225 : 250  = 9: 10

答案 - D

解释

Required % = {(30000/122.5*1000)*100}% = (300/1225*100)% = 1200/49% = 25%

答案 - B

解释

(2005, 2006):
X : (175+125)= 300
Y : (200+175)= 375
(2000, 2001)
X : (175+200)= 375
Y :	(225+150)= 375

Thus total production of x = total production of Y in 2000 and 2001.

答案 - C

解释

For commodity x, we have:
In 2001, increase% = (25/175*100)% =  14.3%
In 2002 , increase% = (75/200*100)% = 37.5%
In 2003, increase% = (125/275*100)% =  45.45%
In 2004 , increase% = (50/150*100)% = 33.5%
In 2005, increase% = (25/200*100)% =  12.5%
In 2006 , increase% = (50/175*100)% = 28.5%
So, it was the maximum  decrement in 2003.

答案 - D

解释

Average production = 1400/7 lakh tons = 200 lakh tons.

答案 - A

解释

X + Y in 2000, 2001 and 2002 = (400+350+525)lakh tons = 1275 lakh tons.
X + Y in 2004, 2005 and 2006 = (450+375+300)= 1125 lakh tons
∴ Required ratio = 1275: 1125 = 17:15

答案 - D

解释

Required ratio = 1300:1400 = 13:14