- 能力倾向有用资源
- 能力倾向 - 问答
连锁规则 - 例题解析
答案 - C
解释
Let the required cost be Rs x. More dolls, more cost (direct) ∴ 15 : 39:: 35 : x ⇒15 *x = (39 *35) ⇒ x= (39 *35)/15 = 91. ∴ Cost of 39 dolls = Rs 91
答案 - D
解释
Let the required number of days be x. Less men, more days (indirect) ∴ 15: 36:: 25 : x ⇒ 15 *x = (36 * 25) ⇒ x= (36 *25 ) / 15 = 60. ∴ Required number of days = 60.
答案 - D
解释
Let the required length be x metres. More men, more length built (direct) Less days, less length built (direct) Men 20 : 25 :: 112 : x Days 6:3 ∴ (20 * 6 *x ) = ( 25 * 3 *112) ⇒ x= (25 * 3 * 112) / (20 * 6 ) = 70. Required length 70m.
题4 - 如果8个男人每天工作9小时,可以在10天内建造一堵长18米、宽2米、高12米的墙,那么需要多少个男人才能在8天内,每天工作6小时,建造一堵长32米、宽3米、高9米的墙?
答案 - A
解释
let the required number of men be x. More length, more men (Direct) More breadth, more men (Direct) Less height, less men (Direct) Less hours per day, more men (Indirect) Less days, more men (Indirect) Length 18:32 Breadth 2:3 Height 12:9 :: 8 : x Hrs / Day 6: 9 Days 8:10 ∴ ( 18 * 2 * 12 * 6 * 8 * x) = ( 32 * 3 * 9 * 9 * 10) ⇒ x= 32*3*9*9*10 / 18*2*12*6*8 =30.
题5 - 一份合同要在56天内完成,并安排了104名工人,每人每天工作8小时。30天后,完成了2/5的工作。为了按时完成工作,可以额外雇佣多少人,每人现在每天工作9小时?
答案 - C
解释
Remaining work = (1- 2/5 ) = 3/5 , Remaining period = (56 – 30) =26 days. Let the additional men employed be x. More work , more men (direct) More days , less men (indirect) More hrs/ day, less men (indirect) Work 2/5 : 3/5 Days 26: 30 :: 104 : (104 + x) Hrs/ day 9:8 ∴ 2/5 *26 * 9 * (104 +x ) = 3/5 *30 * 8 * 104 ⇒ (104 +x) = 3 * 30 * 8 * 104 / 2* 26 * 9 = 160 ⇒ x = (160 – 104) = 56. Additional men to be employed = 56.
答案 - D
解释
9 women = 5 men ⇒ 1 women = 5/9 men ⇒ 6 women = (5/9 * 6) men = 10/3 men. 3 men +6 women = (3+ 10/3 ) men = 19/3 men. Let the required number of days be x. More men, less days 19/3 : 5 :: 19 : x ⇒ 19 /3 *x = (5 *19) ⇒ x= (5* 19 * 3 /19 ) = 15. ∴ Required number of days = 15.
答案 - D
解释
1 women can complete the work in (10 * 8) days= 80 days. 1 child can complete the work in (16 * 10) days= 160 days. 1 women 1 days work = 1/80 , 1 child 1 days work= 1/160. (10 women +12 children) 1 days work = ( 10 * 1/80 +12 * 1/160) = ( 1/8 + 3/40 ) = 8/ 40 = 1 /5. ∴ 10 women and 12 children will finish the work in 5 days.
题8 - 如果6台发动机每天运行9小时,消耗15公吨煤炭,那么8台发动机每天运行12小时需要多少煤炭,已知前一种类型的3台发动机消耗的煤炭与后一种类型的4台发动机一样多?
答案 - D
解释
Let the required quantity of coal consumed be x tones. More engines, more coal consumption (direct) More hours, more coal consumption (direct) Less rate of consumption, less consumption (direct) Engines 6:8 Working Hrs 9:12 :: 15 : x Rate of consumption 1/3 : 1/4 ∴ (6 * 9 * 1/3 * x) = (8 * 12 * 1/4 * 15 ⇒ 18x = 360 ⇒ x = 20. Quantity of coal consumed = 20 tonnes.
答案 - A
解释
Let the required weight be x kg. Less length, less weight (direct) 22.5: 6 :: 85.5 :x ⇒ 22.5x = (6 * 85.5) ⇒ x= (6 * 85.5) / 22.5 = (6 *885 / 225) = 22.8 kg. Required weight = 22.8 kg.
题10 - 在地图比例尺中,1.5厘米代表24公里。如果地图上两点之间的距离是76.5厘米,那么这两点之间的实际距离是多少?
答案 - B
解释
Let the actual distance be x km. More distance on the map, more is actual distance (direct) 1.5 : 76.5 :: 24 : x ⇒ 1.5x = (76.5 * 24) ⇒ x = (76.5 * 24) / 1.5 = 1224 km. Required distance= 1224km.
答案 - D
解释
Let the required cost be Rs x. More eggs, more cost ( direct) 72: 132 :: 48 : x ⇒ 72 x = (132 * 48) ⇒ x= (132 *48) / 72 = 88. ∴ Required cost = Rs 88.
答案 - A
解释
Let the required distance be x km. More time , more distance covered ( direct) 20: 50: :: 5 : x ⇒ 20x = (50 * 5 ) ⇒ x= (50 * 5) / 20 = 12.5 km. Required distance = 12.5 km.
aptitude_chain_rules.htm
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