比例 - 例题详解



题1 - 如果a:b=2:3 且 b:c=5:7,求a:c。

A - 10:11

B - 10:21

C - 21:10

D - 11:10

答案 - B

解释

We have a/b = 2/3 and b/c = 5/7 
So a/c = (a/b*b/c) = (2/3*5/7) = 10/21 
So its demonstrate that a:c = 10:21

题2 - 如果a:b=2:3 且 b:c=5:7,求a:b:c。

A - 10:15:21

B - 10:21:15

C - 15:10:21

D - 11:10:21

答案 - A

解释

Here a/b = 2/3 and b/c = 5:7 = 3/5*5:3/5*7 = 3:21/5. 
So a:b=2:3 and b:c=3:21/5 
So a:b:c = 2:3:21/5 = 10:15:21. 

题3 - 如果4a = 5b 且 8b = 9c,求a:b:c。

A - 45:36:32

B - 45:32:36

C - 32:45:36

D - 32:36:45

答案 - A

解释

4a = 5b
=> a/b=5/4
and 8b = 9c
=> b/c=9/8 
So a:b = 5:4 and b:c = 9:8 = (4/9)(9):(4/9)(8) = 4:32/9 
=> a:b:c = 5:4:32/9 = 45:36:32. 
Hence,a:b:c = 45:36:32. 

题4 - 如果a/8 = b/9 = c/12,求a:b:c。

A - 8:12:9

B - 8:9:12

C - 12:8:12

D - 9:8:12

答案 - B

解释

Let a/8 = b/9 =c/12 =k. 
Then a=8k ,b=9k and c=12k. 
So a:b:c = 8k:9k:12k =8:9:12. 
Hence,a:b:c = 8:9:12.

题5 - 如果a:b =1:3,b:c = 5:7 且 c:d = 9:8,求a:b:c:d。

A - 45:15:63:56

B - 63:45:15:56

C - 15:45:63:56

D - 15:63:45:56

答案 - C

解释

We have a:b = 1:3, b:c = 5:7 and c:d = 9:8 
=> a:b = 5:15, b:c = 15:21, c:d =(21/9)*9 : (21/9)*8 
=> a:b = 5:15, b:c = 15:21, c:d = 21:56/3  
=> a:b:c:d =5:15:21:56/3 = 15:45:63:56 
Consequently, a:b:c:d = 15:45:63:56 

题6 - 如果(5x+3y): (5x-3y) =3:1,则x:y=?

A - 6:5

B - 7:8

C - 8:9

D - 9:11

答案 - A

解释

Here (5x+3y)/(5x-3y) = 3/1  
=> 5x+3y = 15x-9y
=> 10x = 12y
=> x/y = 12/10 = 6/5 
So x:y =6:5 

题7 - 如果x:y= 5:3,则( 8x-5y) : (8x+5y) = ?

A - 6:11

B - 7:11

C - 8:11

D - 5:11

答案 - D

解释

Given x/y = 5/3 
Dividing numerator and denominator by y.
(8x-5y)/(8x+5y) = {8(x/y) - 5}/{8(x/y) + 5}
= {8*(5/3)-5}/{8*(5/3)+5}
= (40-15)/(40+15)
= 25/55
= 5/11 
So (8x-5y):(8x+5y)= 5:11

题8 - 求4, 5和12的第四比例项。

A - 18

B - 16

C - 14

D - 15

答案 - D

解释

Let 4:5::12:x. 
=> 4*x = (5*12) 
=> x = 5*12/4
= 15 
So the fourth relative to 4,5,12 is 15. 

题9 - 求9和12的第三比例项。

A - 18

B - 16

C - 14

D - 15

答案 - B

解释

Third relative to 9 and 12 is equivalent to fourth corresponding to 9,12 and 12. 
Give it a chance to be x at that point 
=> 9:12::12:x 
=> 9x = 12*12 
=> x = 12*12/9
=16 
So the third relative is 16. 

题10 - 求49和64的比例中项。

A - 58

B - 56

C - 54

D - 55

答案 - B

解释

Mean relative somewhere around 49 and 64 is 49*64 = (7*8) = 56. 

题11 - 总计391元分给a、b、c,比例为1/2:2/3:3/4,求每个人的份额。

A - 102,136,153

B - 112,114,123

C - 114,117,129

D - 122,134,123

答案 - A

解释

We have a:b:c=1/2:2/3:3/4= 6:8:9. 
A share = (391*6/23) = 102 rs. 
B offer = (391*8/23) = 136 rs. 
C offer = (391*9/23) = 153 rs.

题12 - 一个袋子装有一元、五角和二角五分的硬币,比例为8:9:11,如果袋子里的总金额是122元,求每种硬币的数量。

A - 8,64,72,88

B - 16,32,72,88

C - 8,64,128,88

D - 32,64,128,88

答案 - A

解释

Let the quantity of one rupee, 50-p and 25-p coins be 8x, 9x and 11x individually. 
At that point, 8x + 9x/2 + 11x/4 =122 
=> 32x + 18x + 11x = 488
=> 61x =488 
=> x = 8 
No. of one rupee coins = 8*8= 64 
No. of 50-p coins =9*8= 72 
No. of 25-p coins =11*8 =88 

题13 - 一种混合物中酒精和水的比例为4:3,如果加入7升水,酒精和水的比例变为3:4。求混合物中酒精的量。

A - 12升

B - 13升

C - 14升

D - 15升

答案 - B

解释

Let the amount of liquor and water be 4x liter and 3x liter separately.
At that point , 4x/3x + 7 = 3/4 
=> 16x = 9x+21 
=> 7x = 21 
so estimation of x is 3 
Amount of liquor in the blend is = 4*3 =12 liters. 

题14 - 在一个班级里,学习文科、商科和理科的学生人数比例为4:7:9。如果文科、商科和理科的学生人数分别增加30%、20%和40%,新的比例是多少?

A - 26:42:63

B - 36:42:63

C - 46:42:63

D - 56:42:63

答案 - A

解释

Let the no. of understudy in expressions, business and science be 4x,7x and 9x individually. 
Presently they are 130% of 4x, 120 % of 7x and 140 % of 9x. 
Required proportion = (130/100*4x): (120/100*7x) (140/100*9x) 
=26x/5:42x/5:63x/5
=26:42:63.

题15 - 汽车的制造成本由三部分组成:材料成本、人工成本和间接成本。一年内,这些成本的比例为4:3:2。第二年,材料成本上涨10%,人工成本上涨8%,但间接成本下降5%。求汽车成本的百分比增长。

A - 44/9 %

B - 54/9 %

C - 64/9 %

D - 74/9 %

答案 - A

解释

Let the expense of material, work and over head be rs. 4x, 3x and 2x separately. 
At that point aggregate expense =9x rs . 
New cost= {(110% of 4x) + (108% of 3x) +(90% of 2x)} 
={(110/100*4x)+(108/100*3x)+(90/100*2x)} 
= (22x/5 + 81x/25 + 9x/5)
= (110x+81x+45x)/25= 236x/25 
Increment = {(236x/25)-9x} = 11x/25 
Increase%= (11x/25)*(1/9x)*100 % 
= 44/9 % 

题16 - 一所学校里男生和女生的比例为3:2。如果20%的男生和25%的女生是奖学金获得者,求非奖学金获得者的百分比。

A - 64 %

B - 78 %

C - 84 %

D - 76 %

答案 - B

解释

Let the no. of young men be 3x and the no. of young ladies 2x. 
Aggregate no. = 5x 
No. of the individuals who are not grant holders 
= (80% of 3x)+(75% of 2x) 
= (80/100 * 3x) + ( 75/100 * 2x) 
= (12x/5 + 3x/2)
= 39x/10 
Required % = (39x/10)*(1/5x)*100 %
= 78% 

题17 - A和B两人共有1210元。如果A的4/15等于B的2/5,B有多少元?

A - 484

B - 284

C - 384

D - 584

答案 - A

解释

Let (4/15)a = (2/5)b = x 
then a = 15x/4 and b = 5x/2 
So. 15x/4 + 5x/2 =1210 
=> 15x + 10x = 4840 
=> 25x = 4840 
=> x=193.6 
So. B = (5/2*193.6) = 484 
Henceforth B has Rs. 484.

题18 - 如果(x+y): (x-y)= 4:1,则(x2+y2): (x2-y2)=?

A - 17/8

B - 19/8

C - 15/8

D - 13/8

答案 - A

解释

(x + y)/(x - y)= 4/1
=> x + y = 4x-4y
=> 3x = 5y
=> x/y = 5/3
Now (x2+y2)/ (x2-y2)=  {(x/y)2+1}/ { (x/y )2-1 }
= {(5/3)2+1} / {(5/2)2 -1} 
= 34/16 = 17/8 

题19 - 如果(4x2-3y2) :( 2x2+5y2)= 12:19,则x:y=?

A - 2:1

B - 3:2

C - 4:1

D - 5:2

答案 - B

解释

(4x2 -3y2)/ (2x2 +5y2) = 12/19
=>76x2-57y2 = 24x2+60y2
=> 52x2 = 117y2
=> x2/y2 = 117/52 = 9/4
=> (x/y)2=(3/2)2
=> x/y = 3/2.
=> x:y = 3:2

题20 - 如果x2+y2 = 4xy,则x:y = ?

A - 2:1

B - 3:2

C - 4:1

D - 5:2

答案 - A

解释

As x2+4y2 = 4xy 
=> x2 + 4y2 - 4xy = 0 
=> (x-2y)2 = 0
=> x-2y=0 
=> x = 2y 
=> x/y = 2/1.
=> x:y = 2:1.
aptitude_ratios.htm
广告