- 能力倾向有用资源
- 能力倾向 - 问答
表格 - 例题解析
方向(第1题到第5题):使用下表回答以下问题
餐厅上半年使用的各种食品数量(公斤)
食品名称 | 一月 | 二月 | 三月 | 四月 | 五月 | 六月 |
---|---|---|---|---|---|---|
大米 | 250 | 230 | 210 | 260 | 240 | 220 |
小麦 | 320 | 340 | 280 | 290 | 300 | 360 |
糖 | 240 | 210 | 200 | 210 | 160 | 150 |
豆类 | 360 | 300 | 320 | 245 | 235 | 250 |
蔬菜 | 380 | 390 | 385 | 375 | 355 | 370 |
其他 | 460 | 485 | 440 | 460 | 475 | 480 |
答案 - C
解释
Quantity of sugar used in April = 210 Kg Total quantity of food items used in april month = (260+290+210+245+375+460) kg = 1860 kg Required% = (210/1840*100)% = 11.4% ≅ 11%
答案 - D
解释
Average quantity of rice used = (250+230+210+260+240+220)/6 = 1410/6 = 235 kg Average quantity of wheat used =(320+340+280+290+300+360) = 1890/6 = 315 kg Required difference = (315-235)= 90 kg
答案 - D
解释
Average quantity of misc. items = (460+485+440+460+475+480)/6 =2800/6 = 466.67 kg
答案 - C
解释
Total quantity of pulses consumed =(360+300+320+245+235+250) =1710 kg Total quantity of vegetable consumed = (380+390+385+375+355+370 )=2255Kg Required difference = (2255-1710)= 545 kg
答案 - C
解释
total quantity of food items consumed in march =(210+280+200+245+375+460)=1835 total quantity of food items consumed in april =(260+290+210+245+375+460) =1840kg required ratio = 1835: 1840 = 367:368
方向(第6题到第10题):使用下表回答以下问题
各个工厂六个班次的工人数量。
班次\工厂 | L | M | N | O | P |
---|---|---|---|---|---|
上午7点到11点 | 7.5 | 8.0 | 7.8 | 7.59 | 8.32 |
上午11点到下午3点 | 6.38 | 7.0 | 7.16 | 6.5 | 7.5 |
下午3点到晚上7点 | 6.5 | 7.28 | 6.35 | 6.15 | 7.24 |
晚上7点到晚上11点 | 7.8 | 5.25 | 6.0 | 6.0 | 6.5 |
晚上11点到凌晨3点 | 5.5 | 5.0 | 5.10 | 5.5 | 5.7 |
凌晨3点到上午7点 | 4.2 | 3.0 | 4.12 | 3.5 | 2.15 |
答案 - D
解释
Total number of workers from factory O =(7.59+6.5+6.15+6+5.5+3.5)thousand =(35.24*1000)= 35240 Total number of workers from factory L =(7.5+6.38+6.5+7.8+5.5+4.2) =(37.88 *1000) =37880 ∴ Required % =( 35240/ 37880* 100)% = 93.03%= 93%
答案 - C
解释
Average number of workers in factory P = (8.32+7.5+7.24+6.5+5.7+2.15)/6 *1000 =37410 /6 = 6235
答案 - A
解释
Total number of workers in factory M =(8+7+7.28+5.25+5+3)*1000= (35.53*1000) =35530 Total number of workers in factory O = 35240 Required difference =(35530- 35240 ) =290
答案 - B
解释
Number of workers in factories Land M in the shift of 11 p.m to 3.am. =(5.5+5)*1000 = (10.5*1000) = 10500. Numbers of workers in factories O and P in the shift of 11 p.m to 3.am =(5.5+5.7)*1000 = (11.2*1000) =11200 Required ratio = 10500 : 11200 = 15 : 16
答案 - D
解释
Average number of workers working in the shift of 7 a.m to 11a.m from all factories =(7.5+8+7.8+7.59+8.32)*1000/5 = 39210/5 = 7842 Average number of workers working in the shift of 7 a.m to 11p.m from all factories =(7.8+5.25+6+6+6.5)*1000 /5 = 31550/5 = 6310 Required total = 7842- 6310 = 14152
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