- 能力倾向实用资源
- 能力倾向 - 问答
折扣 - 例题解析
答案 - B
解释
P.W.= ((100 x Amount))/(100+(R x T)) = Rs {(100 x 9920)/(100 (3 x 8))} = Rs (100 x 9920)/124 = Rs 8000
答案 - A
解释
P.W. = ((100 x T.D.))/((R x T)) = Rs {(100 x 180)/(6 x 3/4)} = Rs 4000
题3 - 一笔3年后到期的款项的真实贴现为200元,而这笔款项在相同时间和相同利率下的简单利息为240元。求这笔款项的金额和利率。
答案 - A
解释
T.D = Rs 200 and S.I. = Rs 240 Sum due = (S .I. x T.D.)/(S.I.-T.D.) = Rs ((240 x 200))/((240-200)) = Rs 1200
答案 - B
解释
P.W. = (Amount)-(T.D.) = Rs (1860-60) = Rs 1800 T.D. is S.I. on P.W. Rs. 60 is S.I. on Rs 1800 at 5% p.a. Time = ((100 x 60))/((5 x 1800)) years = 2/3 years = 2/3 x 12 months = 8 months
答案 - C
解释
P.W.= ((100 x Amount))/(100+(R x T)) = Rs {(100 x 9920)/(100 (3 x 8))} = Rs (100 x 9920)/124 = Rs 8000 T.D. = (Amount)-(P.W.) = Rs (9920-8000) = Rs 1920
答案 - A
解释
P.W. = ((100 x T.D.))/((R x T)) = Rs {(100 x 180)/(6 x 3/4)} = Rs 4000 Sum = (P.W.+T.D.) = Rs (4000+180) = Rs 4180
题7 - 一笔3年后到期的款项的真实贴现为200元,而这笔款项在相同时间和相同利率下的简单利息为240元。求利率。
答案 - D
解释
T.D = Rs 200 and S.I. = Rs 240 Sum due = (S .I. x T.D.)/(S.I.-T.D.) = Rs ((240 x 200))/((240-200)) = Rs 1200 T.D is S.I. on the sum. Rs. 240 is S.I. on Rs 1200 for a long time. R= ((100 x 240))/((1200 x 3))% p.a. = 20/3% p.a
答案 - D
解释
Amount = Rs 2575, T=4/12 years = 1/3 years, T.D = Rs. 75 P.W. = (Amount) - (T.D.) = Rs (2575-75) = 2500. T.D. Is S.I. on P.W. R.s 75 is S.I. on Rs. 2500 or 1/3 years Rate = ((100x75)/(2500x1/3))% p.a. = 9% p.a.
答案 - B
解释
T.D. = Rs 26.25, T = 10/12 year= 5/6 year,R=6% p.a. Let P.W. be Rs x. Then, S.I. on Rs x at 6% p.a. for 5/6 year is Rs. 26.25 ∴ (x * 6 * 5/6)/100 = 25.25 => x= (26.25 * 20) = 525 ∴ (P.W.) + (T.D.) = Rs. (525+26.25) = Rs 551.25
答案 - B
解释
S.I. = Rs. (x * 6 * 1/2)/100 = Rs. 3x/100 and T.D. = Rs {(x * 78/12)/(100+(6 * 6/12) )} = Rs. 3x/103 ∴ 3x/100-3x/103 = 27 => (309x-300x) = (27 * 100 * 103) => x = ((27*100*103))/9 = 30900
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