能力倾向 - 日历在线测验

以下测验提供与日历相关的多项选择题 (MCQ)。您需要阅读所有给出的答案，然后点击正确的答案。如果您不确定答案，可以使用显示答案按钮查看答案。您可以使用下一测验按钮查看测验中的新一组问题。

Q 1 - 2005年3月哪些日期是星期五？

A - 5^th、12^th、17^th 和 24^th

B - 4^th、11^th、18^th 和 25^th

C - 6^th、13^th、20^th 和 27^th

D - 7^th、14^th、21^th 和 28^th

答案：B

解释

To begin with we discover the day on 1.3.2005.
1.3.2005= (2004 year+ period from 1.1.2005 to 1.3.2005

Odd days in 1600 years = 0
Odd days in 400 years = 0

4 years = (1 jump year+ 3 normal years)
= (1*2+3*1) odd days = 5 odd days. 

Jan + Feb + March
31 + 28 + 1 = 60 days = (8 weeks +4 days)=4 odd days.
∴ Total number of odd days = (0+0+5+4) =9=2 odd days.

∴ 1.3.2005 was Tuesday. So, Friday lies on 4.3.2005.
Thus, Friday lies on 4th, 11th, 18th and 25th of March, 2005.

Q 2 - 2007年1月1日是星期一。2008年1月1日是星期几？

答案：B

解释

The year 2007 is a common year.
So, it has 1 odd day.

First day of the year 2007 was Monday.
First day of the year 2008 will be 1 day past Monday.
Subsequently, it will be Tuesday.

Q 3 - 2008年1月1日是星期二。2009年1月1日是星期几？

答案：C

解释

The year 2008 is a jump year.
So, it has 2 odd days.
First day of the year 2008 is Tuesday (Given).

In this way, first day of the year 2009 is 
2 days past Tuesday.
Subsequently, it will be Thursday.

Q 4 - 2005年3月6日是星期一。2004年3月6日是星期几？

答案：B

解释

The year 2004 is a jump year. 
In this way, it has 2 odd days.
∴ The day on sixth March, 2005 will be 2 days.

past the day on sixth Walk, 2004.
Yet, sixth March, 2005 is Monday.
∴ sixth March, 2004 is Saturday.

Q 5 - 1988年6月17日是星期几？

答案：D

解释

17th June, 1998= (1997 year Period structure 1.1.1998 to 17.6.1998)
Odd days in 1600 year=0.
Odd days in 300 year = (5*3) =1.
97 year has 24 jump year +73 standard years.
= 24*2 + 73*1
= 48 + 73
= 121 odd days
= 17 weeks + 2 odd days = 2 odd days
= 2 odd days.
∴ 1998 years have (0+1+2) = 3 odd days

Jan to June = (31+29+31+30+31)
= 152 days

Add 17 days of June.
= 152 + 17
= 169 days
= 24 weeks + 1 days
= 1 odd day.

∴ Total number of odd day = 3 + 1 = 4 odd days.
Hence 17.06.1998 was Thursday.

Q 6 - 2006年5月28日是星期几？

答案：D

解释

28.May,2006 =(2005 years +Period structure 1.1.2006 to 28.5.2006)
Odd days in 1600 years=0.
Odd days in 400 years = 0.

5 years = (4 common years+ 1 jump years)=(4*1+1*2)odd days
= 6 odd days.

Jan + Feb. + March + April + May
31 + 28 + 31 + 30 + 28 =148 days.

148 days = (21 weeks+1 day) = 1 odd day
Aggregate no. of odd days = (0+0+6+1) = 7= 0 odd day.
 
Given day is Sunday.

Q 7 - 今天是星期一。61天后是星期几？

答案：B

解释

Each day of the week is rehashed following 7 days.
In this way, after 63 days it will be Monday.
∴ Following 61 days , it will be Saturday.

Q 8 - x个星期x天共有多少天？

答案：B

解释

x weeks x days=(7x+x) days=8x days.

Q 9 - 2006年1月1日是星期日。求2010年1月1日是星期几。

答案：C

解释

On 31st December,2005 it was Saturday.
Number of odd days frame the year 2006 to the year 2009=(1+1+2+1)=5 days.

∴ On 31st December 2009 , it was Thursday.
In this way, on first jan, 2010 it is Friday.

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